(p+q)Cp{ }^{(p+q)} C_{p}(p+q)Cp
(p+q)Cq(p+q) C_{q}(p+q)Cq
(p+q)Cp−q{ }^{(p+q)} C_{p-q}(p+q)Cp−q
(p−q)C(p+q){ }^{(p-q)} C_{(p+q)}(p−q)C(p+q)
Answer:A,B