C2H5OH(1)+H2SO4(1)\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}(1)+\mathrm{H}_{2} \mathrm{SO}_{4}(1)C2H5OH(1)+H2SO4(1)=C2H5−OSO3H(1)+H2( g)=\mathrm{C}_{2} \mathrm{H}_{5}-\mathrm{OSO}_{3} \mathrm{H}(1)+\mathrm{H}_{2}(\mathrm{~g})=C2H5−OSO3H(1)+H2( g)
C6H5−C≡N+2H2OHClΔ\mathrm{C}_{6} \mathrm{H}_{5}-\mathrm{C} \equiv \mathrm{N}+2 \mathrm{H}_{2} \mathrm{O} \frac{\mathrm{HCl}}{\Delta}C6H5−C≡N+2H2OΔHCl→C6H5−COOH+NH3+CO2\rightarrow \mathrm{C}_{6} \mathrm{H}_{5}-\mathrm{COOH}+\mathrm{NH}_{3}+\mathrm{CO}_{2}→C6H5−COOH+NH3+CO2
(CH3CO)2O(1)+NH3( g)Δ\left(\mathrm{CH}_{3} \mathrm{CO}\right)_{2} \mathrm{O}(1)+\mathrm{NH}_{3}(\mathrm{~g})^{\Delta}(CH3CO)2O(1)+NH3( g)ΔCH3CO−NH2( s)+CH3COOH(1)\mathrm{CH}_{3} \mathrm{CO}-\mathrm{NH}_{2}(\mathrm{~s})+\mathrm{CH}_{3} \mathrm{COOH}(1)CH3CO−NH2( s)+CH3COOH(1)
উপরের সবগুলো বিক্রিয়াই সঠিক
A & C
