1st circle ⊂2nd circle 1^{\text {st }} \text { circle } \subset 2^{\text {nd }} \text { circle }1st circle ⊂2nd circle
2nd circle ⊂3rd circle 2^{\text {nd }} \text { circle } \subset 3^{\text {rd }} \text { circle }2nd circle ⊂3rd circle
1st circle ∪2nd circle ∪3rd circle =3rd circle 1^{\text {st }} \text { circle } \cup 2^{\text {nd }} \text { circle } \cup 3^{\text {rd }} \text { circle }=3^{\text {rd }} \text { circle }1st circle ∪2nd circle ∪3rd circle =3rd circle
1st circle ∩2nd circle ∩3rd circle ={(0,0)}1^{\text {st }} \text { circle } \cap 2^{\text {nd }} \text { circle } \cap 3^{\text {rd }} \text { circle }=\{(0,0)\}1st circle ∩2nd circle ∩3rd circle ={(0,0)}
1st circle ∩2nd circle ∩3rd circle =∅1^{\text {st }} \text { circle } \cap 2^{\text {nd }} \text { circle } \cap 3^{\text {rd }} \text { circle }=\emptyset1st circle ∩2nd circle ∩3rd circle =∅
Answer:A,B,C