sin(270∘+θ)=−cosθ\sin \left(270^{\circ}+\theta\right)=-\cos \thetasin(270∘+θ)=−cosθ
cos(−θ)=−cosθ\cos (-\theta)=-\cos \thetacos(−θ)=−cosθ
tan(180∘+θ)=tanθ\tan \left(180^{\circ}+\theta\right)=\tan \thetatan(180∘+θ)=tanθ
tan(360∘−θ)=tanθ\tan \left(360^{\circ}-\theta\right)=\tan \thetatan(360∘−θ)=tanθ
Answer:A & C
