μ0B2πI\frac{\mu_{0} B}{2 \pi I}2πIμ0B
μ0I2πa\frac{\mu_{0} I}{2 \pi a}2πaμ0I
μ0I4πa\frac{\mu_{0} I}{4 \pi a}4πaμ0I
4πaμ0I\frac{4 \pi a}{\mu_{0} I}μ0I4πa