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IUT_16-17
HSC - রসায়ন ২য় পত্র
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অধ্যায়-০২ঃ জৈব রসায়ন
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Following equation is a part of preparing:
2
C
H
C
I
F
2
→
90
0
∘
C
C
F
2
=
C
F
2
+
2
H
C
l
\mathrm {2CHCIF_2 \xrightarrow{900^\circ \mathrm C} CF_2=CF_2+2HCl}
2CHCI
F
2
90
0
∘
C
C
F
2
=
C
F
2
+
2HCl
A.
Polythene
B.
Teflon
C.
Ploysterene
D.
PVC
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