P(A∪B)=1P(A \cup B)=1P(A∪B)=1
P(A∩B)=1P(A \cap B)=1P(A∩B)=1
P(A∪B)=0P(A \cup B)=0P(A∪B)=0
P(A∩B)=0P(A \cap B)=0P(A∩B)=0