বাস্তব সংখ্যায় $\frac{1}{|3 x+1|} \geq 5$ অসমতাটির সমাধান-

$\left(-\frac{2}{3},-\frac{1}{3}\right) \cup\left(-\frac{1}{3},-\frac{4}{5}\right)$

$\left(-\frac{2}{3},-\frac{1}{3}\right) \cup\left(-\frac{1}{3},-\frac{4}{15}\right)$

$\left(-\frac{2}{3},-\frac{4}{15}\right)$

$\text { None }$