f=uvu+v\mathrm{f}=\dfrac{u v}{u+v}f=u+vuv
1f=1v+1u\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}f1=v1+u1
1f=u+vuv\dfrac{1}{f}=\dfrac{u+v}{u v}f1=uvu+v
f=u+vuvf=\dfrac{u+v}{u v}f=uvu+v