$\mathrm{2^{2}+4^{2}+6^{2}+\ldots . .+(4 n)^{2}=}$ কত?

$\mathrm{\frac{4}{3}n(2n + 1) (4n + 1)}$

$\mathrm{\frac{3}{4}n(2n + 1) (4n + 1)}$

$\mathrm{\frac{4}{3}(2n + 1) (4n + 1)}$

$\mathrm{\frac{4}{3}n(2n + 1) }$