2tan2θ1+tan22θ\dfrac{2 \tan 2 \theta}{1+\tan ^{2} 2 \theta}1+tan22θ2tan2θ
2tan2θ1−tan22θ\dfrac{2 \tan 2 \theta}{1-\tan ^{2} 2 \theta}1−tan22θ2tan2θ
2tanθ1−tan2θ\dfrac{2 \tan \theta}{1-\tan ^{2} \theta}1−tan2θ2tanθ
1−tan22θ1+tan22θ\dfrac{1-\tan ^{2} 2 \theta}{1+\tan ^{2} 2 \theta}1+tan22θ1−tan22θ