2cosθ2n−12 \cos \frac{\theta}{2^{n-1}}2cos2n−1θ
2cosθ2n2 \cos \frac{\theta}{2^{n}}2cos2nθ
2cosθ2n+12 \cos \frac{\theta}{2^{n+1}}2cos2n+1θ
2cosnθ22 \cos \frac{n \theta}{2}2cos2nθ
2cosθ2n2 \cos \frac{\theta}{2 n}2cos2nθ