DiB_2022

37Li+X24He+42He{ }_{3}^{7} \mathrm{Li}+\mathrm{X} \rightarrow{ }_{2}^{4} \mathrm{He}+\frac{4}{2} \mathrm{He} এখানে X হলো—

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{ }_{3}^{7} Li+X \rightarrow{ }_{2}^{4} He+\frac{4}{2} He এখানে X হলো—