110+i310\frac{1}{10}+i \frac{3}{10}101+i103
i3+1\frac{i}{3}+13i+1
110+i(−3)10\frac{1}{10}+i \frac{(-3)}{10}101+i10(−3)
14+i34\frac{1}{4}+i \frac{3}{4}41+i43