rA+rB=dAB\mathrm{r}_{\mathrm{A}}+\mathrm{r}_{\mathrm{B}}=\mathrm{d}_{\mathrm{AB}}rA+rB=dAB
rA+rB<dAB\mathrm{r}_{\mathrm{A}}+\mathrm{r}_{\mathrm{B}}<\mathrm{d}_{\mathrm{AB}}rA+rB<dAB
rA+rB>dABr_{A}+r_{B}>d_{A B}rA+rB>dAB
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