n2−112\frac{\mathrm{n}^{2}-1}{12}12n2−1
n2+112\frac{\mathrm{n}^{2}+1}{12}12n2+1
n2−112\sqrt{\frac{n^{2}-1}{12}}12n2−1
n−112\frac{\mathrm{n}-1}{12}12n−1
