a2+1a2=a3+1a3a^{2}+\frac{1}{a^{2}}=a^{3}+\frac{1}{a^{3}} a2+a21=a3+a31
a2+1a2=a4+1a4a^{2}+\frac{1}{a^{2}}=a^{4}+\frac{1}{a^{4}} a2+a21=a4+a41
1a2+1a4=a2+1a2\frac{1}{a^{2}}+\frac{1}{a^{4}}=a^{2}+\frac{1}{a^{2}}a21+a41=a2+a21
a2−1a2=a4−1a4a^{2}-\frac{1}{a^{2}}=a^{4}-\frac{1}{a^{4}}a2−a21=a4−a41
Correct Answer not Found
