A∪B=B∪A\mathrm {A \cup B=B \cup A}A∪B=B∪A
(A∪B)∪C=A∪(B∪C)\mathrm {(A \cup B) \cup C=A \cup(B \cup C)}(A∪B)∪C=A∪(B∪C)
(A∩B)′=A′∪B′\mathrm {(A \cap B)^{\prime}=A^{\prime} \cup B^{\prime}}(A∩B)′=A′∪B′
A∩B′=A−B\mathrm{A \cap B^{\prime}=A-B}A∩B′=A−B