r2+6rcosθ−1=0r^{2}+6 r \cos \theta-1=0r2+6rcosθ−1=0
r2−5rsinθ−1=0r^{2}-5 r \sin \theta-1=0r2−5rsinθ−1=0
r2=5rsinθr^{2}=5 r \sin \thetar2=5rsinθ
r2+6rcosθ−5rsinθ−.l=0r^{2}+6 r \cos \theta-5 r \sin \theta-. l=0r2+6rcosθ−5rsinθ−.l=0