n(n+1)2\mathrm {\frac{n(n+1)}{2}}2n(n+1)
{n(n+1)2}2\left\{\frac{\mathrm{n}(\mathrm{n}+1)}{2}\right\}^{2}{2n(n+1)}2
n(n+1)(2n+1)6\mathrm {\frac{n(n+1)(2 n+1)}{6}}6n(n+1)(2n+1)
n(n+1)24\mathrm {\frac{n(n+1)^{2}}{4}}4n(n+1)2