F→=qE→\overrightarrow{\mathrm{F}}=\mathrm{q} \overrightarrow{\mathrm{E}}F=qE
$$\rm{\overrightarrow{F}=q(\overrightarrow{v} \times \overrightarrow{B})}$
F→=q(E→+v→×B→)\rm{\overrightarrow{F}=q(\overrightarrow{E}+\overrightarrow{v} \times \overrightarrow{B})}F=q(E+v×B)
F→=E→q\overrightarrow{\mathrm{F}}=\dfrac{\overrightarrow{\mathrm{E}}}{\mathrm{q}}F=qE