x+23=y−11=z−3−5\frac{x+2}{3}=\frac{y-1}{1}=\frac{z-3}{-5}3x+2=1y−1=−5z−3
x−2=y+12=z˙+3−2x-2=\frac{y+1}{2}=\frac{\dot{z}+3}{-2}x−2=2y+1=−2z˙+3
x+2=y+1−2=z+32x+2=\frac{y+1}{-2}=\frac{z+3}{2}x+2=−2y+1=2z+3
x−2=y−12=z−3−2x-2=\frac{y-1}{2}=\frac{z-3}{-2}x−2=2y−1=−2z−3