An electron of mass of $9.1 \times 10^{-31}$ kg is revolving around a nucleus in a circular path of a radius of $0.53 \times 10^{-10}$ 10-1.m. Calculate the angular velocity of the electron.

$4.13 \times 10^{16} \mathrm{rads}^{-1}$

$4.13 \times 10^{15} \mathrm{rads}^{-1}$

$4.13 \times 10^{14} \mathrm{rads}^{-1}$

$5.13 \times 10^{17} \mathrm{rads}^{-1}$