2αp1−α\frac{2 \alpha \mathrm{p}}{1-\alpha}1−α2αp
2α×P1+α\frac{2 \alpha \times \mathrm{P}}{1+\alpha}1+α2α×P
α×P1+α\frac{\alpha \times \mathbf{P}}{1+\alpha}1+αα×P
α×Pa−α\frac{\alpha \times \mathbf{P}}{a-\alpha}a−αα×P
