12πMk1+k2\frac{1}{2 \pi} \sqrt{\frac{M}{k_{1}+k_{2}}}2π1k1+k2M
12πk1+k2M\frac{1}{2 \pi} \sqrt{\frac{k_{1}+k_{2}}{M}}2π1Mk1+k2
2πk1+k2M2 \pi \sqrt{\frac{k_{1}+k_{2}}{M}}2πMk1+k2