F→=q(v→×B→)\overrightarrow{\mathrm{F}}=\mathrm{q}(\overrightarrow{\mathrm{v}} \times \overrightarrow{\mathrm{B}})F=q(v×B)
F⃗=v⃗×B⃗q\vec{F}=\frac{\vec{v} \times \vec{B}}{q}F=qv×B
F→=v→×B→\overrightarrow{\mathrm{F}}=\overrightarrow{\mathrm{v}} \times \overrightarrow{\mathrm{B}}F=v×B
F⃗=qE⃗+v⃗B⃗\vec{F}=q \vec{E}+\vec{v} \vec{B}F=qE+vB