Search
Bookmarks
My requests
Create/Join exam
Test Series
Mock tests
?
Sign In
Click to login or register
Toggle Sidebar
পিএসসি ও অন্যান্য_2018
সাধারণ গণিত
→
অধ্যায় ০২ঃ বীজগণিত
→
সূচক ও লগারিদম
log
k
(
a
n
b
n
)
+
log
k
(
b
n
c
n
)
+
log
k
(
c
u
a
n
)
=
\log _{k}\left(\frac{a^{\mathrm{n}}}{b^{\mathrm{n}}}\right)+\log _{\mathrm{k}}\left(\frac{\mathrm{b}^{\mathrm{n}}}{\mathrm{c}^{\mathrm{n}}}\right)+\log _{\mathrm{k}}\left(\frac{\mathrm{c}^{\mathrm{u}}}{\mathrm{a}^{\mathrm{n}}}\right)=
lo
g
k
(
b
n
a
n
)
+
lo
g
k
(
c
n
b
n
)
+
lo
g
k
(
a
n
c
u
)
=
কত?
A.
a
b
\frac{a}{b}
b
a
B.
log
k
a
b
\log_k\frac{a}{b}
lo
g
k
b
a
C.
log
k
b
c
\log_k\frac{b}{c}
lo
g
k
c
b
D.
0
Guide Answer
Add Answer
?
Loading answers...
Home
Search
Exam
Mock
Saved