2nπ2 \mathrm{n} \pi2nπ
(2nπ+1)π(2 n \pi+1) \pi(2nπ+1)π
2nπ+π/42 n \pi+\pi / 42nπ+π/4
(2n−1)π(2 n-1) \pi(2n−1)π